Java對象相等比較(Equals)
以下代碼顯示如何實現equals()
和hashCode()
方法
class Point {
private int x;
private int y;
public Point(int x, int y) {
this.x = x;
this.y = y;
}
/* implement the equals() method */
public boolean equals(Object otherObject) {
// Are the same?
if (this == otherObject) {
return true;
}
// Is otherObject a null reference?
if (otherObject == null) {
return false;
}
// Do they belong to the same class?
if (this.getClass() != otherObject.getClass()) {
return false;
}
// Get the reference of otherObject in a SmartPoint variable
Point otherPoint = (Point) otherObject;
// Do they have the same x and y co-ordinates
boolean isSamePoint = (this.x == otherPoint.x && this.y == otherPoint.y);
return isSamePoint;
}
/*
* implement hashCode() method of the Object class, which is a requirement
* when you implement equals() method
*/
public int hashCode() {
return (this.x + this.y);
}
}
public class Main {
public static void main(String[] args) {
Point pt1 = new Point(10, 10);
Point pt2 = new Point(10, 10);
Point pt3 = new Point(12, 19);
Point pt4 = pt1;
System.out.println("pt1 == pt1: " + (pt1 == pt1));
System.out.println("pt1.equals(pt1): " + pt1.equals(pt1));
System.out.println("pt1 == pt2: " + (pt1 == pt2));
System.out.println("pt1.equals(pt2): " + pt1.equals(pt2));
System.out.println("pt1 == pt3: " + (pt1 == pt3));
System.out.println("pt1.equals(pt3): " + pt1.equals(pt3));
System.out.println("pt1 == pt4: " + (pt1 == pt4));
System.out.println("pt1.equals(pt4): " + pt1.equals(pt4));
}
}
上面的代碼生成以下結果。
pt1 == pt1: true
pt1.equals(pt1): true
pt1 == pt2: false
pt1.equals(pt2): true
pt1 == pt3: false
pt1.equals(pt3): false
pt1 == pt4: true
pt1.equals(pt4): true
這裏是equals()
方法實現的規範。 假設x
,y
和z
是三個對象的非空引用。
- 自反性。 表達式
x.equals(x)
應該返回true
。 - 對稱性。 如果
x.equals(y)
返回true
,那麼y.equals(x)
也必須返回true
。 - 傳遞性。如果
x.equals(y)
返回true
,那麼y.equals(z)
也返回true
,則x.equals(z)
必須返回true
。 - 一致性。如果
x.equals(y)
返回true
,它應該保持返回true
,直到x
或y
的狀態被修改。 如果x.equals(y)
返回false
,它應該保持返回false
,直到x
或y
的狀態被修改。 - 與
null
引用的比較:任何類的對象不應等於null
引用。 表達式x.equals(null)
應始終返回false
。 - 與
hashCode()
方法的關係:如果x.equals(y)
返回true
,x.hashCode()
必須返回與y.hashCode()
相同的值。